CVE-2026-44335 - PraisonAI has an SSRF bypass

📡 GitHub-Advisory · 2026-05-06

CVE-2026-44335 - PraisonAI has an SSRF bypass

CVE-2026-44335

GHSA-q9pw-vmhh-384g HIGH pip/praisonaiagents

CVE: CVE-2026-44335

Summary

The URL checking logic in PraisonAI has a logical flaw that could be bypassed by attackers, leading to SSRF attacks.

Details

The current PraisonAI project uses _validate_url to validate the input URL. The main logic is to perform security checks on the host portion of the URL extracted by urlparse to prevent SSRF attacks.

<img width="1290" height="1145" alt="QQ20260424-151256-24-1" src="https://github.com/user-attachments/assets/d5f16b74-5ad2-444f-8600-b05f78a4b769" />

However, there are indeed differences in parsing between urlparse and the library that actually sends the request. Currently, almost all application scenarios in this project involve first using _validate_url for URL validation, and then using _get_session().get to send the request.

<img width="1143" height="740" alt="QQ20260424-151437-24-2" src="https://github.com/user-attachments/assets/b1bf6ec2-d32a-4dac-b814-da819e8d3c83" />

In reality, its underlying mechanism is requests.get.

<img width="1042" height="576" alt="QQ20260424-151645-24-3" src="https://github.com/user-attachments/assets/e17352c3-4205-44d6-ab6e-75566480215b" />

The core issue: urlparse() and requests disagree on which host a URL like http://127.0.0.1:6666\@1.1.1.1 points to:

  • urlparse() treats \ as a regular character and @ as the userinfo-host delimiter, so it extracts hostname as 1.1.1.1 (public)
  • requests treats \ as a path character, connecting to 127.0.0.1 (internal)

Below is a test code I wrote following the code.

import sys
from pathlib import Path
from pprint import pprint

sys.path.insert(0, str(Path(r"D:/BaiduNetdiskDownload/PraisonAI-main/PraisonAI-main/src/praisonai-agents")))

from praisonaiagents.tools import spider_tools

# url = "http://127.0.0.1:6666\@1.1.1.1"
url = "http://127.0.0.1:6666"

result = spider_tools.scrape_page(url)

if isinstance(result, dict) and "error" in result:
    print("scrape failed:", result["error"])
else:
    pprint(result)

When an attack


📌 来源: GitHub-Advisory | 🆔 CVE-2026-44335 | 📅 2026-05-06

[!] CONTACT_CHANNELS

如需商务合作、技术咨询或漏洞反馈,请通过以下离岸节点联系作者。

> PING_AUTHOR (@A1RedTeam)